What is the solution for (dx)/(dt)=x(100-x) ?

The solution for (dx)/(dt)=x(100-x) is x=(100)/(-e^{-100t-c_{1)}+1}

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(dx)/(dt)=x(100-x)

\frac{d x}{d t} = x (100 - x)

x = \frac{100}{- e ^{- 100 t - c_{1}} + 1}

Solution steps

\frac{d x}{d t} = x (100 - x)

Solve Bernoulli ODE:

x = \frac{100}{- e ^{- 100 t - c_{1}} + 1}

x = \frac{100}{- e ^{- 100 t - c_{1}} + 1}

\int e^{- \frac{x}{4}} d x

y = \frac{6 x}{x + 5}, (- 3, - 9)

x^{6} y^{^{'}} + x^{5} y = 0

\frac{d}{d x} (\frac{x}{x + 1})

y = 3 x, y = 3 x

What is the solution for (dx)/(dt)=x(100-x) ?
The solution for (dx)/(dt)=x(100-x) is x=(100)/(-e^{-100t-c_{1)}+1}