What is (\partial)/(\partial y)(22cos(x)yz^2) ?

The answer to (\partial)/(\partial y)(22cos(x)yz^2) is 22z^2cos(x)

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(\partial)/(\partial y)(22cos(x)yz^2)

\frac{\partial}{\partial y} (22 cos (x) y z^{2})

22 z^{2} cos (x)

Solution steps

\frac{\partial}{\partial y} (22 cos (x) y z^{2})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 22 cos (x) z^{2} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= 22 cos (x) z^{2} \cdot 1

Simplify

= 22 z^{2} cos (x)

x - x^{2}

\int 8 x + 6 d x

\frac{\partial}{\partial y} ((y - 5) (x + 5)^{2})

\frac{d}{d x} (x^{4} - 20 x^{2} + 64)

\int 8 cos^{3} (2 θ) sin (2 θ) d θ

What is (\partial)/(\partial y)(22cos(x)yz^2) ?
The answer to (\partial)/(\partial y)(22cos(x)yz^2) is 22z^2cos(x)