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Popular >

y^'+2/t y=4t

Solution

y^{^{'}} + \frac{2}{t} y = 4 t

Solution

y = t^{2} + \frac{c _{1}}{t ^{2}}

Solution steps

y^{'} (t) + \frac{2}{t} y = 4 t

Solve linear ODE:

y = t^{2} + \frac{c _{1}}{t ^{2}}

y = t^{2} + \frac{c _{1}}{t ^{2}}

Popular Examples

integral of 1/x sqrt(1+1/(x^4))

\int \frac{1}{x} 1 + \frac{1}{x ^{4}} d x

y^{''}+4y^'+3y=32xe^x

y^{^{''}} + 4 y^{^{'}} + 3 y = 32 x e^{x}

integral of x^5cos(x)

\int x^{5} cos (x) d x

tangent of f(x)=(6x)/(x^2+1)tangent of

f (x) = \frac{6 x}{x ^{2} + 1}

derivative of 3x(18x^4+(13/(x+1)))

\frac{d}{d x} (3 x (18 x^{4} + \frac{13}{x + 1}))

Frequently Asked Questions (FAQ)

What is the solution for y^'+2/t y=4t ?
The solution for y^'+2/t y=4t is y=t^2+(c_{1})/(t^2)