What is the tangent of xy=-121 ?

The tangent of xy=-121 is y=(121)/(a_{0)^2}x-(242)/(a_{0)}

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tangent of xy=-121

tangent of

x y = - 121

y = \frac{121}{a _{0}^{2}} x - \frac{242}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - \frac{121}{a _{0}})

Find the slope of

x y = - 121 : \frac{d y}{d x} = \frac{121}{x ^{2}}

Compute the slope of

x y = - 121

x = a_{0} : m = \frac{121}{a _{0}^{2}}

Find the line with slope m=

\frac{121}{a _{0}^{2}}

and passing through

(a_{0}, - \frac{121}{a _{0}}) : y = \frac{121}{a _{0}^{2}} x - \frac{242}{a _{0}}

y = \frac{121}{a _{0}^{2}} x - \frac{242}{a _{0}}

y = 12 e^{2} x

3 + 7 t + t^{2}

x \to - 8 + lim (\frac{- 9 x}{x + 8})

\frac{d}{d x} (2 x^{2} + 3 x + 2)

\int \frac{1}{x ^{2} - 8 x + 15} d x

What is the tangent of xy=-121 ?
The tangent of xy=-121 is y=(121)/(a_{0)^2}x-(242)/(a_{0)}