What is the sum from n=2 to infinity of n/(n+1) ?

The sum from n=2 to infinity of n/(n+1) is diverges

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sum from n=2 to infinity of n/(n+1)

n = 2 \sum \infty \frac{n}{n + 1}

diverges

Solution steps

n = 2 \sum \infty \frac{n}{n + 1}

Apply Series Divergence Test:

diverges

= diverges

x \to 5 lim (x^{2} - 25)

\int \frac{2}{( x ^{2} - 3 x + 2 )} d x

t^{5} e^{- 6 t}

f (t) = \frac{t}{t ^{2} + 7}

\int_{1}^{e^{5}} \frac{ln ^{2} ( x ^{2} )}{x} d x

What is the sum from n=2 to infinity of n/(n+1) ?
The sum from n=2 to infinity of n/(n+1) is diverges