What is the derivative of y=3x+sin(5x) ?

The derivative of y=3x+sin(5x) is 3+cos(5x)*5

What is the first derivative of y=3x+sin(5x) ?

The first derivative of y=3x+sin(5x) is 3+cos(5x)*5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = 3 x + sin (5 x)

3 + cos (5 x) \cdot 5

Solution steps

\frac{d}{d x} (3 x + sin (5 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (sin (5 x))

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (sin (5 x)) = cos (5 x) \cdot 5

= 3 + cos (5 x) \cdot 5

\frac{d}{d x} ((x^{2} - x)^{4})

\int \frac{x ^{2} + y ^{2} - 5}{( 1 + x ) ^{3}} d x

\frac{d}{d x} (a^{2} + x^{2})

\frac{d v}{d t} = \frac{t}{sin ( v )}

\frac{d}{d x} (e^{x} (6 x^{2} - 12 x + 12))

What is the derivative of y=3x+sin(5x) ?
The derivative of y=3x+sin(5x) is 3+cos(5x)*5
What is the first derivative of y=3x+sin(5x) ?
The first derivative of y=3x+sin(5x) is 3+cos(5x)*5