What is the integral from 0 to 1 of sqrt(x+1) ?

The integral from 0 to 1 of sqrt(x+1) is (4sqrt(2)-2)/3

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integral from 0 to 1 of sqrt(x+1)

\int_{0}^{1} x + 1 d x

\frac{4 2 - 2}{3}

Decimal Notation

1.21895 \dots

Solution steps

\int_{0}^{1} x + 1 d x

Apply u-substitution

: \int_{1}^{2} u d u

= \int_{1}^{2} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{2}

= [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{2}

Compute the boundaries:

\frac{4 2}{3} - \frac{2}{3}

= \frac{4 2}{3} - \frac{2}{3}

Simplify

= \frac{4 2 - 2}{3}

- csc (x) - cos (x)

x \to 2 lim (h (x))

\int 3 x e^{9 x} d x

\frac{d}{d x} (\frac{50}{x})

\frac{d y}{d x} - 2 x y = - 3 x^{2} e^{x^{2}}

What is the integral from 0 to 1 of sqrt(x+1) ?
The integral from 0 to 1 of sqrt(x+1) is (4sqrt(2)-2)/3