What is the derivative of 4x^3-2/(x^3) ?

The derivative of 4x^3-2/(x^3) is 12x^2+6/(x^4)

What is the first derivative of 4x^3-2/(x^3) ?

The first derivative of 4x^3-2/(x^3) is 12x^2+6/(x^4)

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\frac{d}{d x} (4 x^{3} - \frac{2}{x ^{3}})

12 x^{2} + \frac{6}{x ^{4}}

Solution steps

\frac{d}{d x} (4 x^{3} - \frac{2}{x ^{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (\frac{2}{x ^{3}})

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (\frac{2}{x ^{3}}) = - \frac{6}{x ^{4}}

= 12 x^{2} - (- \frac{6}{x ^{4}})

Simplify

= 12 x^{2} + \frac{6}{x ^{4}}

y^{^{''}} - y^{^{'}} = - 12

\int \frac{4}{( t ^{2} + 1 ) ^{\frac{3}{2}}} d t

\int_{0}^{1} π (x - x^{8}) d x

\int_{1}^{\infty} x^{- 4} d x

x \to 0 lim (\frac{3 - 3 e ^{- x}}{e ^{x} - 1})

What is the derivative of 4x^3-2/(x^3) ?
The derivative of 4x^3-2/(x^3) is 12x^2+6/(x^4)
What is the first derivative of 4x^3-2/(x^3) ?
The first derivative of 4x^3-2/(x^3) is 12x^2+6/(x^4)