What is the d/(dθ)(4sin(3θ)) ?

The d/(dθ)(4sin(3θ)) is 12cos(3θ)

What is the first d/(dθ)(4sin(3θ)) ?

The first d/(dθ)(4sin(3θ)) is 12cos(3θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d θ} (4 sin (3 θ))

12 cos (3 θ)

Solution steps

\frac{d}{d θ} (4 sin (3 θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d θ} (sin (3 θ))

Apply the chain rule:

cos (3 θ) \frac{d}{d θ} (3 θ)

= cos (3 θ) \frac{d}{d θ} (3 θ)

\frac{d}{d θ} (3 θ) = 3

= 4 cos (3 θ) \cdot 3

Simplify

= 12 cos (3 θ)

(2 x + e^{y}) d x + x e^{y} d y = 0

\int t e^{3 t} + e^{t} d t

\int \frac{11 x ^{3}}{2 + x ^{2}} d x

\frac{d}{d x} ((1 + \frac{7}{x})^{x})

\frac{d}{d x} (x^{3} - 2 x + 3)