What is the derivative of sin(x^{2x}) ?

The derivative of sin(x^{2x}) is cos(x^{2x})*2x^{2x}(ln(x)+1)

What is the first derivative of sin(x^{2x}) ?

The first derivative of sin(x^{2x}) is cos(x^{2x})*2x^{2x}(ln(x)+1)

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\frac{d}{d x} (sin (x^{2 x}))

cos (x^{2 x}) \cdot 2 x^{2 x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (sin (x^{2 x}))

Apply the chain rule:

cos (x^{2 x}) \frac{d}{d x} (x^{2 x})

= cos (x^{2 x}) \frac{d}{d x} (x^{2 x})

\frac{d}{d x} (x^{2 x}) = 2 x^{2 x} (ln (x) + 1)

= cos (x^{2 x}) \cdot 2 x^{2 x} (ln (x) + 1)

x \to 5 lim (\frac{∣ x - 5 ∣}{5 - x})

\frac{d}{d x} ((x + 5)^{3})

(0, 0), (- 2, - 6)

y^{^{'}} - 4 y = 3 e^{5 t}

\frac{\partial}{\partial x} (3 y^{2} sin (6 x))

What is the derivative of sin(x^{2x}) ?
The derivative of sin(x^{2x}) is cos(x^{2x})*2x^{2x}(ln(x)+1)
What is the first derivative of sin(x^{2x}) ?
The first derivative of sin(x^{2x}) is cos(x^{2x})*2x^{2x}(ln(x)+1)