What is (\partial)/(\partial x)(xy+1/x+8/y) ?

The answer to (\partial)/(\partial x)(xy+1/x+8/y) is y-1/(x^2)

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(\partial)/(\partial x)(xy+1/x+8/y)

\frac{\partial}{\partial x} (x y + \frac{1}{x} + \frac{8}{y})

y - \frac{1}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (x y + \frac{1}{x} + \frac{8}{y})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (\frac{1}{x}) + \frac{\partial}{\partial x} (\frac{8}{y})

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{\partial}{\partial x} (\frac{8}{y}) = 0

= y - \frac{1}{x ^{2}} + 0

Simplify

= y - \frac{1}{x ^{2}}

n = 1 \sum \infty \frac{1}{( 3 + 2 n ) ^{2}}

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\int - 3 ln (2 x + 1) d x

7 e^{x} arctan (x)

What is (\partial)/(\partial x)(xy+1/x+8/y) ?
The answer to (\partial)/(\partial x)(xy+1/x+8/y) is y-1/(x^2)