What is the (-6sin(6x))^' ?

The (-6sin(6x))^' is -36cos(6x)

What is the first (-6sin(6x))^' ?

The first (-6sin(6x))^' is -36cos(6x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(- 6 sin (6 x))^{^{'}}

- 36 cos (6 x)

Solution steps

(- 6 sin (6 x))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 6 (sin (6 x))^{^{'}}

Apply the chain rule:

cos (6 x) (6 x)^{'}

= cos (6 x) (6 x)^{'}

(6 x)^{'} = 6

= - 6 cos (6 x) \cdot 6

Simplify

= - 36 cos (6 x)

\frac{d}{d x} (\frac{1}{8 x + 3})

\int (- 5 e^{x} + \frac{4}{x}) d x

ln (\frac{a - b x}{a - c x})

\frac{d}{d y} (x y^{2})

\int t sin (k t) d t