What is area y=-x^2+8x,y=x^2-6x ?

The answer to area y=-x^2+8x,y=x^2-6x is 343/3

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area y=-x^2+8x,y=x^2-6x

area

y = - x^{2} + 8 x, y = x^{2} - 6 x

\frac{343}{3}

Decimal Notation

114.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{7} - x^{2} + 8 x - (x^{2} - 6 x) d x

Solve

\int_{0}^{7} - x^{2} + 8 x - (x^{2} - 6 x) d x : \frac{343}{3}

The area is:

= \frac{343}{3}

\frac{d}{d x} ((x^{2} - 2 x - 1) (\frac{x + 1}{x + 3}))

\int \frac{1}{( 4 - x ) ^{2}} d x

(y) d x - (x + y^{2} - x^{2}) d y = 0

\int \frac{54}{1 - cos ( 9 x )} d x

(2 x)^{^{'}}

What is area y=-x^2+8x,y=x^2-6x ?
The answer to area y=-x^2+8x,y=x^2-6x is 343/3