What is the derivative of (cos(x)/(1+asin(x))) ?

The derivative of (cos(x)/(1+asin(x))) is (-sin(x)(1+asin(x))-acos^2(x))/((1+asin(x))^2)

What is the first derivative of (cos(x)/(1+asin(x))) ?

The first derivative of (cos(x)/(1+asin(x))) is (-sin(x)(1+asin(x))-acos^2(x))/((1+asin(x))^2)

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\frac{d}{d x} (\frac{cos ( x )}{1 + a sin ( x )})

\frac{- sin ( x ) ( 1 + a sin ( x ) ) - a cos ^{2} ( x )}{( 1 + a sin ( x ) ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{cos ( x )}{1 + a sin ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( cos ( x ) ) ( 1 + a sin ( x ) ) - \frac{d}{d x} ( 1 + a sin ( x ) ) cos ( x )}{( 1 + a sin ( x ) ) ^{2}}

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d}{d x} (1 + a sin (x)) = a cos (x)

= \frac{( - sin ( x ) ) ( 1 + a sin ( x ) ) - a cos ( x ) cos ( x )}{( 1 + a sin ( x ) ) ^{2}}

Simplify

\frac{( - sin ( x ) ) ( 1 + a sin ( x ) ) - a cos ( x ) cos ( x )}{( 1 + a sin ( x ) ) ^{2}} : \frac{- sin ( x ) ( 1 + a sin ( x ) ) - a cos ^{2} ( x )}{( 1 + a sin ( x ) ) ^{2}}

= \frac{- sin ( x ) ( 1 + a sin ( x ) ) - a cos ^{2} ( x )}{( 1 + a sin ( x ) ) ^{2}}

\int \frac{6}{1 + x ^{2}} d x

x \to 1 lim (f (x) + g (x))

n = 2 \sum \infty \frac{n}{2 n ^{2} - 3}

\frac{\partial}{\partial x} (e^{- x y} + y^{3} x^{4})

\frac{d}{d x} (3 x^{3} + 2 x^{2} - 1 x + 5)

What is the derivative of (cos(x)/(1+asin(x))) ?
The derivative of (cos(x)/(1+asin(x))) is (-sin(x)(1+asin(x))-acos^2(x))/((1+asin(x))^2)
What is the first derivative of (cos(x)/(1+asin(x))) ?
The first derivative of (cos(x)/(1+asin(x))) is (-sin(x)(1+asin(x))-acos^2(x))/((1+asin(x))^2)