What is the derivative of-x^2-3x+4 ?

The derivative of-x^2-3x+4 is -2x-3

What is the first derivative of-x^2-3x+4 ?

The first derivative of-x^2-3x+4 is -2x-3

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\frac{d}{d x} (- x^{2} - 3 x + 4)

- 2 x - 3

Solution steps

\frac{d}{d x} (- x^{2} - 3 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= - 2 x - 3 + 0

Simplify

= - 2 x - 3

\int \frac{1}{a ^{2} - u ^{2}} d u

\int \frac{1}{x ( 2 + x )} d x

θ^{^{''}} + \frac{a}{b} \cdot θ = 0

f (x) = x e^{4 x + s i n (x) - 10}

\frac{\partial}{\partial x} (2 e^{x yz} sin (x w))

What is the derivative of-x^2-3x+4 ?
The derivative of-x^2-3x+4 is -2x-3
What is the first derivative of-x^2-3x+4 ?
The first derivative of-x^2-3x+4 is -2x-3