What is the integral from 2 to 5 of 1/x ?

The integral from 2 to 5 of 1/x is ln(5)-ln(2)

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integral from 2 to 5 of 1/x

\int_{2}^{5} \frac{1}{x} d x

ln (5) - ln (2)

Decimal Notation

0.91629 \dots

Solution steps

\int_{2}^{5} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{2}^{5}

Compute the boundaries:

ln (5) - ln (2)

= ln (5) - ln (2)

x^{2} - 1

\int_{1}^{4} 8 x ln (x) d x

\int (x^{3} + 4 x y) d x

\int_{0}^{1} (x^{2} + 1) (e^{- x}) d x

\frac{1}{s ^{2} + 4 s + 8}

What is the integral from 2 to 5 of 1/x ?
The integral from 2 to 5 of 1/x is ln(5)-ln(2)