What is the derivative of g(x)= 3/(sqrt(6x+8)) ?

The derivative of g(x)= 3/(sqrt(6x+8)) is -9/((6x+8)^{3/2)}

What is the first derivative of g(x)= 3/(sqrt(6x+8)) ?

The first derivative of g(x)= 3/(sqrt(6x+8)) is -9/((6x+8)^{3/2)}

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derivative of

g (x) = \frac{3}{6 x + 8}

- \frac{9}{( 6 x + 8 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{3}{6 x + 8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{6 x + 8})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((6 x + 8)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( 6 x + 8 ) ^{\frac{3}{2}}} \frac{d}{d x} (6 x + 8)

= - \frac{1}{2 ( 6 x + 8 ) ^{\frac{3}{2}}} \frac{d}{d x} (6 x + 8)

\frac{d}{d x} (6 x + 8) = 6

= 3 (- \frac{1}{2 ( 6 x + 8 ) ^{\frac{3}{2}}} \cdot 6)

Simplify

3 (- \frac{1}{2 ( 6 x + 8 ) ^{\frac{3}{2}}} \cdot 6) : - \frac{9}{( 6 x + 8 ) ^{\frac{3}{2}}}

= - \frac{9}{( 6 x + 8 ) ^{\frac{3}{2}}}

\int x^{2} - 2 x - 3 d x

(1 - 2 y + x) \frac{d y}{d x} + y = 2 x - 1

x \to 2 lim (e^{x} + e^{- x})

\int sin (1 - 2 x) cos (1 + 2 x) d x

x \to 0 lim (\frac{x ^{4} + 3 x}{x})

What is the derivative of g(x)= 3/(sqrt(6x+8)) ?
The derivative of g(x)= 3/(sqrt(6x+8)) is -9/((6x+8)^{3/2)}
What is the first derivative of g(x)= 3/(sqrt(6x+8)) ?
The first derivative of g(x)= 3/(sqrt(6x+8)) is -9/((6x+8)^{3/2)}