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Popular >

sum from n=1 to infinity of (4/10)^n*3

Solution

n = 1 \sum \infty (\frac{4}{10})^{n} \cdot 3

Solution

2

Solution steps

n = 1 \sum \infty (\frac{4}{10})^{n} \cdot 3

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 3 \cdot n = 1 \sum \infty (\frac{4}{10})^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= 3 (n = 0 \sum \infty (\frac{4}{10})^{n} - (\frac{4}{10})^{0})

n = 0 \sum \infty (\frac{4}{10})^{n} = \frac{5}{3}

= 3 (\frac{5}{3} - (\frac{4}{10})^{0})

Simplify

3 (\frac{5}{3} - (\frac{4}{10})^{0}) : 2

= 2

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Frequently Asked Questions (FAQ)

What is the sum from n=1 to infinity of (4/10)^n*3 ?
The sum from n=1 to infinity of (4/10)^n*3 is 2