What is the (cos(sqrt(x)))^' ?

The (cos(sqrt(x)))^' is -(sin(sqrt(x)))/(2sqrt(x))

What is the first (cos(sqrt(x)))^' ?

The first (cos(sqrt(x)))^' is -(sin(sqrt(x)))/(2sqrt(x))

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(cos (x))^{^{'}}

- \frac{sin ( x )}{2 x}

Solution steps

(cos (x))^{'}

Apply the chain rule:

- sin (x) (x)^{'}

= - sin (x) (x)^{'}

(x)^{'} = \frac{1}{2 x}

= - sin (x) \frac{1}{2 x}

Simplify

- sin (x) \frac{1}{2 x} : - \frac{sin ( x )}{2 x}

= - \frac{sin ( x )}{2 x}

\int \frac{e ^{x} - e ^{- x}}{e ^{2 x}} d x

x \to 3 lim ([3 (8) (- 10)])

\int \frac{8}{t + 1} + t d t

\frac{d}{d x} (e^{x y}) = \frac{d}{d x} (2 y)

\frac{\partial}{\partial x} (- e^{- x} y - e^{- x})

What is the (cos(sqrt(x)))^' ?
The (cos(sqrt(x)))^' is -(sin(sqrt(x)))/(2sqrt(x))
What is the first (cos(sqrt(x)))^' ?
The first (cos(sqrt(x)))^' is -(sin(sqrt(x)))/(2sqrt(x))