What is derivative of f(x)=((480t)/((t^2+5)^3)) ?

The answer to derivative of f(x)=((480t)/((t^2+5)^3)) is (dt)/(dx)=0

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derivative of f(x)=((480t)/((t^2+5)^3))

derivative of

f (x) = (\frac{480 t}{( t ^{2} + 5 ) ^{3}})

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{480 t}{( t ^{2} + 5 ) ^{3}}

Treat

t

t (x)

Differentiate both sides:

0 = \frac{2400 \frac{d t}{d x} ( - t ^{2} + 1 )}{( t ^{2} + 5 ) ^{4}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int \frac{x ( y ^{2} - 5 y + 6 )}{x ^{2} + 1} d x

x \to 5 lim (in (x^{2} - 25))

\int \frac{1}{x + 1 - x} d x

x \to 1 lim (\frac{( x )}{x - 1})

\int \frac{x + 1}{( x ^{2} + 2 x ) ^{2}} d x

What is derivative of f(x)=((480t)/((t^2+5)^3)) ?
The answer to derivative of f(x)=((480t)/((t^2+5)^3)) is (dt)/(dx)=0