What is area y=sqrt(6x-2),(1,3) ?

The answer to area y=sqrt(6x-2),(1,3) is 56/9

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area y=sqrt(6x-2),(1,3)

area

y = 6 x - 2, (1, 3)

\frac{56}{9}

Solution steps

Apply the area formula:

\int_{1}^{3} 6 x - 2 d x

Solve

\int_{1}^{3} 6 x - 2 d x : \frac{56}{9}

The area is:

= \frac{56}{9}

f (x) = \frac{2 x}{x + 1}

\frac{d}{d x} (\frac{x + 2}{x ^{2} - 4})

\frac{d}{d x} (\frac{6 x ^{2} + 2 x + 8}{x})

y = 3 x^{3} - x^{2} + 8, (2, 28)

\frac{d}{d x} (\frac{ln ( x )}{2})