What is the derivative of f(x)=2x^2-3x+1 ?

The derivative of f(x)=2x^2-3x+1 is 4x-3

What is the first derivative of f(x)=2x^2-3x+1 ?

The first derivative of f(x)=2x^2-3x+1 is 4x-3

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derivative of

f (x) = 2 x^{2} - 3 x + 1

4 x - 3

Solution steps

\frac{d}{d x} (2 x^{2} - 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 4 x - 3 + 0

Simplify

= 4 x - 3

x \to 0 lim (\frac{100}{x ^{2}})

\int (x - 6) sin (π x) d x

cos^{3} (t)

\frac{d}{d x} (\frac{- 3}{x ^{4}})

\int_{0}^{π} 4 cos^{4} (x) sin (x) d x

What is the derivative of f(x)=2x^2-3x+1 ?
The derivative of f(x)=2x^2-3x+1 is 4x-3
What is the first derivative of f(x)=2x^2-3x+1 ?
The first derivative of f(x)=2x^2-3x+1 is 4x-3