What is the limit as x approaches 0 of 5/(1+x) ?

The limit as x approaches 0 of 5/(1+x) is 5

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limit as x approaches 0 of 5/(1+x)

x \to 0 lim (\frac{5}{1 + x})

5

Solution steps

x \to 0 lim (\frac{5}{1 + x})

Plug in the value

x = 0

= \frac{5}{1 + 0}

Simplify

= 5

n = 0 \sum \infty (0.5 + 0.5 i)^{n}

y = (sin (2 x^{3} - 1))^{2}

\int_{1}^{3} 19 r^{3} ln (r) d r

y^{^{''}} + 5 y^{^{'}} + 4 y = t e^{- t}

\int \frac{x ^{3} - 3 x + 2}{( x + 1 ) ( x - 1 ) ^{3}} d x

What is the limit as x approaches 0 of 5/(1+x) ?
The limit as x approaches 0 of 5/(1+x) is 5