What is the derivative of 4cos(5x) ?

The derivative of 4cos(5x) is -20sin(5x)

What is the first derivative of 4cos(5x) ?

The first derivative of 4cos(5x) is -20sin(5x)

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\frac{d}{d x} (4 cos (5 x))

- 20 sin (5 x)

Solution steps

\frac{d}{d x} (4 cos (5 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (cos (5 x))

Apply the chain rule:

- sin (5 x) \frac{d}{d x} (5 x)

= - sin (5 x) \frac{d}{d x} (5 x)

\frac{d}{d x} (5 x) = 5

= 4 (- sin (5 x) \cdot 5)

Simplify

= - 20 sin (5 x)

\frac{d}{d x} (- \frac{1}{2} e^{- x})

\frac{d}{d x} (- \frac{6 x ^{2} - 6}{x ^{3} - 3 x + 2})

\int (5 + 9 x)^{8} (9) d x

\int \frac{cos ^{3} ( x )}{sin ( x )} d x

\int \frac{2 x + 4}{x ^{2} + 5 x - 6} d x

What is the derivative of 4cos(5x) ?
The derivative of 4cos(5x) is -20sin(5x)
What is the first derivative of 4cos(5x) ?
The first derivative of 4cos(5x) is -20sin(5x)