What is laplacetransform-9t ?

The answer to laplacetransform-9t is -9/(s^2)

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laplacetransform-9t

laplace transform

- 9 t

- \frac{9}{s ^{2}}

Solution steps

L {- 9 t}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 9 L {t}

L {t} : \frac{1}{s ^{2}}

= - 9 \cdot \frac{1}{s ^{2}}

Refine

- 9 \frac{1}{s ^{2}} : - \frac{9}{s ^{2}}

= - \frac{9}{s ^{2}}

\int sin^{2} (9 x) d x

\int_{0}^{3} - x + 2 d x

\int 6 x^{5} 3 x^{4} + 2 d x

y = 9 x, y = 70 - x^{2}

\int (\frac{5}{x}) d x