What is the tangent of y= 1/(3+2x),(2, 1/7) ?

The tangent of y= 1/(3+2x),(2, 1/7) is y=-2/49 x+11/49

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tangent of y= 1/(3+2x),(2, 1/7)

tangent of

y = \frac{1}{3 + 2 x}, (2, \frac{1}{7})

y = - \frac{2}{49} x + \frac{11}{49}

Solution steps

Find the slope of

y = \frac{1}{3 + 2 x} : \frac{d y}{d x} = - \frac{2}{( 3 + 2 x ) ^{2}}

Compute the slope of

y = \frac{1}{3 + 2 x}

(2, \frac{1}{7}) : m = - \frac{2}{49}

Find the line with slope m=

- \frac{2}{49}

and passing through

(2, \frac{1}{7}) : y = - \frac{2}{49} x + \frac{11}{49}

y = - \frac{2}{49} x + \frac{11}{49}

7 x - 6 y x^{2} + 1 \frac{d y}{d x} = 0

\frac{d y}{d x} = (e^{4 x + 3 y})

(sin (π) x)^{^{'}}

\frac{d}{d x} (ln (sin (x)))

\int_{3}^{\infty} \frac{1}{x ^{3}} d x

What is the tangent of y= 1/(3+2x),(2, 1/7) ?
The tangent of y= 1/(3+2x),(2, 1/7) is y=-2/49 x+11/49