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Popular >

y^'+4y=8

Solution

y^{^{'}} + 4 y = 8

Solution

y = - e^{- 4 t - c_{1}} + 2

Solution steps

y^{'} (t) + 4 y = 8

Solve separable ODE:

y = - e^{- 4 t - c_{1}} + 2

y = - e^{- 4 t - c_{1}} + 2

Popular Examples

laplacetransform t(5t^3+8t^2+10)laplace transform

t (5 t^{3} + 8 t^{2} + 10)

derivative of {z}(xx)

\frac{d}{d x} (z (x) x)

integral from 0 to 0.1 of xarctan(5x)

\int_{0}^{0.1} x arctan (5 x) d x

integral of 8x^{3/5}+5x^{-4/5}

\int 8 x^{\frac{3}{5}} + 5 x^{- \frac{4}{5}} d x

(dy}{dx}=\frac{(y+1))/x

\frac{d y}{d x} = \frac{( y + 1 )}{x}

Frequently Asked Questions (FAQ)

What is the solution for y^'+4y=8 ?
The solution for y^'+4y=8 is y=-e^{-4t-c_{1}}+2