What is the tangent of f(x)=-3x^2-2,\at x=5 ?

The tangent of f(x)=-3x^2-2,\at x=5 is y=-30x+73

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tangent of f(x)=-3x^2-2,\at x=5

tangent of

f (x) = - 3 x^{2} - 2, at x = 5

y = - 30 x + 73

Solution steps

Find the tangent point:

(5, - 77)

Find the slope of

f (x) = - 3 x^{2} - 2 : \frac{df ( x )}{d x} = - 6 x

Compute the slope of

f (x) = - 3 x^{2} - 2

x = 5 : m = - 30

Find the line with slope m=

- 30

and passing through

(5, - 77) : y = - 30 x + 73

y = - 30 x + 73

\int - 4 x e^{x^{2}} d x

\frac{3}{( s - 1 ) ^{2}}

\int \frac{48 x ^{2}}{( x - 15 ) ( x + 5 ) ^{2}} d x

x \to - 3 lim (4 x^{2} + 3 x + 2)

(1 - x^{2}) \frac{d y}{d x} = x y + y

What is the tangent of f(x)=-3x^2-2,\at x=5 ?
The tangent of f(x)=-3x^2-2,\at x=5 is y=-30x+73