What is area y= 1/(x^2),y=0,x=1,x=5 ?

The answer to area y= 1/(x^2),y=0,x=1,x=5 is 4/5

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area y= 1/(x^2),y=0,x=1,x=5

area

y = \frac{1}{x ^{2}}, y = 0, x = 1, x = 5

\frac{4}{5}

Solution steps

Apply the area formula:

\int_{1}^{5} \frac{1}{∣ x ∣ ^{2}} d x

Solve

\int_{1}^{5} \frac{1}{∣ x ∣ ^{2}} d x : \frac{4}{5}

The area is:

= \frac{4}{5}

x \to 0 lim (\frac{sin ( 2 x )}{x} + 4)

\frac{d}{d x} ((2 x^{2} - 4 x)^{\frac{1}{2}})

x \to \infty lim (x^{2} + 3)

\int_{0}^{12} 3 x d x

f (t) = 2 cos (2 t)

What is area y= 1/(x^2),y=0,x=1,x=5 ?
The answer to area y= 1/(x^2),y=0,x=1,x=5 is 4/5