What is the integral of sin(x)cos^2(x) ?

The integral of sin(x)cos^2(x) is -(cos^3(x))/3+C

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integral of sin(x)cos^2(x)

\int sin (x) cos^{2} (x) d x

- \frac{cos ^{3} ( x )}{3} + C

Solution steps

\int sin (x) cos^{2} (x) d x

Apply u-substitution

: \int - u^{2} d u

= \int - u^{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= - \frac{u ^{3}}{3}

Substitute back

u = cos (x)

= - \frac{cos ^{3} ( x )}{3}

Add a constant to the solution

= - \frac{cos ^{3} ( x )}{3} + C

\frac{3 s - 4}{s ^{2} + 4 s + 8}

\frac{d}{d y} (\frac{y - 6}{y ^{2} - 2 y + 12})

\int (e^{3 x} + 1)^{2} d x

y^{^{''}} + 2 y^{^{'}} - 3 = 0

x \to - 5 - lim (\frac{3 x}{2 x + 10})

What is the integral of sin(x)cos^2(x) ?
The integral of sin(x)cos^2(x) is -(cos^3(x))/3+C