What is the derivative of x^2+ln(x) ?

The derivative of x^2+ln(x) is 2x+1/x

What is the first derivative of x^2+ln(x) ?

The first derivative of x^2+ln(x) is 2x+1/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{2} + ln (x))

2 x + \frac{1}{x}

Solution steps

\frac{d}{d x} (x^{2} + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 x + \frac{1}{x}

\frac{\partial}{\partial t} (t e^{\frac{w}{t}})

\int x (4 x + 1) d x

\frac{df}{d t} = 4 t + \frac{9 t}{9 - t ^{2}}

x \cdot y^{2}

x \to 3 lim (- x + 3)

What is the derivative of x^2+ln(x) ?
The derivative of x^2+ln(x) is 2x+1/x
What is the first derivative of x^2+ln(x) ?
The first derivative of x^2+ln(x) is 2x+1/x