What is laplacetransform h(t)=-5t^2 ?

The answer to laplacetransform h(t)=-5t^2 is -(10)/(s^3)

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laplacetransform h(t)=-5t^2

laplace transform

h (t) = - 5 t^{2}

- \frac{10}{s ^{3}}

Solution steps

L {- 5 t^{2}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {t^{2}}

L {t^{2}} : \frac{2}{s ^{3}}

= - 5 \cdot \frac{2}{s ^{3}}

Refine

- 5 \frac{2}{s ^{3}} : - \frac{10}{s ^{3}}

= - \frac{10}{s ^{3}}

\frac{d}{d x} (\frac{5 sin ( x )}{3 + cos ( x )})

\int_{0}^{\frac{5}{2}} \frac{1}{25 + 4 x ^{2}} d x

\int 3 x^{2} - 12 x + 12 d x

\int_{1}^{4} (2 x + x) d x

\int ln (n)

What is laplacetransform h(t)=-5t^2 ?
The answer to laplacetransform h(t)=-5t^2 is -(10)/(s^3)