What is (\partial)/(\partial x)(x-1/y) ?

The answer to (\partial)/(\partial x)(x-1/y) is 1

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(\partial)/(\partial x)(x-1/y)

\frac{\partial}{\partial x} (x - \frac{1}{y})

1

Solution steps

\frac{\partial}{\partial x} (x - \frac{1}{y})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (\frac{1}{y})

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (\frac{1}{y}) = 0

= 1 - 0

Simplify

= 1

\int (2 x + 3) 2 x + 1 d x

\frac{d}{d x} (sech^{2} (3 x))

\int \frac{2 x - 3}{x ^{2} + 4 x + 5} d x

n = 2 \sum \infty \frac{- 1}{n}

\frac{d}{d x} (\frac{x ^{3} - 2 x ^{2} + 2 x - 4}{x ^{2} + 2})

What is (\partial)/(\partial x)(x-1/y) ?
The answer to (\partial)/(\partial x)(x-1/y) is 1