What is the tangent of f(x)=-2sin(x),\at x= 3/4 pi ?

The tangent of f(x)=-2sin(x),\at x= 3/4 pi is y=sqrt(2)x-sqrt(2)-(3pi)/(2sqrt(2))

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tangent of f(x)=-2sin(x),\at x= 3/4 pi

tangent of

f (x) = - 2 sin (x), at x = \frac{3}{4} π

y = 2 x - 2 - \frac{3 π}{2 2}

Solution steps

Find the tangent point:

(\frac{3}{4} π, - 2)

Find the slope of

f (x) = - 2 sin (x) : \frac{df ( x )}{d x} = - 2 cos (x)

Compute the slope of

f (x) = - 2 sin (x)

x = \frac{3}{4} π : m = 2

Find the line with slope m=

2

and passing through

(\frac{3}{4} π, - 2) : y = 2 x - 2 - \frac{3 π}{2 2}

y = 2 x - 2 - \frac{3 π}{2 2}

x^{2} y^{^{'}} + \frac{4}{3} x y = - 2 cos (2 x) y^{- \frac{1}{2}}

n = 1 \sum \infty sin (nπ)

\int_{- 1}^{1} \frac{e ^{2 x}}{1 + e ^{x}} d x

\frac{d}{d x} (\frac{1}{arccos ( x ^{2} + 2 x + 4 )})

f (x) = x^{2}, (- 0.8, 0.64)

What is the tangent of f(x)=-2sin(x),\at x= 3/4 pi ?
The tangent of f(x)=-2sin(x),\at x= 3/4 pi is y=sqrt(2)x-sqrt(2)-(3pi)/(2sqrt(2))