What is the tangent of f(x)= 2/(x+7),(-8,-2) ?

The tangent of f(x)= 2/(x+7),(-8,-2) is y=-2x-18

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tangent of f(x)= 2/(x+7),(-8,-2)

tangent of

f (x) = \frac{2}{x + 7}, (- 8, - 2)

y = - 2 x - 18

Solution steps

Find the slope of

f (x) = \frac{2}{x + 7} : \frac{df ( x )}{d x} = - \frac{2}{( x + 7 ) ^{2}}

Compute the slope of

f (x) = \frac{2}{x + 7}

(- 8, - 2) : m = - 2

Find the line with slope m=

- 2

and passing through

(- 8, - 2) : y = - 2 x - 18

y = - 2 x - 18

\frac{d}{d x} (e^{x} arctan (x))

x (\frac{d y}{d x}) = \frac{1}{y ^{3}}

\frac{d y}{d x} = (x + y + 4)^{2}

\frac{e ^{x}}{5 + 5 x}

\frac{\partial}{\partial y} (e^{2 y} - y cos (x) y)

What is the tangent of f(x)= 2/(x+7),(-8,-2) ?
The tangent of f(x)= 2/(x+7),(-8,-2) is y=-2x-18