What is the integral of (x^2-3)sin(2x) ?

The integral of (x^2-3)sin(2x) is -1/2 x^2cos(2x)+1/2 xsin(2x)+7/4 cos(2x)+C

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integral of (x^2-3)sin(2x)

\int (x^{2} - 3) sin (2 x) d x

- \frac{1}{2} x^{2} cos (2 x) + \frac{1}{2} x sin (2 x) + \frac{7}{4} cos (2 x) + C

Solution steps

\int (x^{2} - 3) sin (2 x) d x

Apply Integration By Parts

: - \frac{1}{2} cos (2 x) (x^{2} - 3) - \int - x cos (2 x) d x

= - \frac{1}{2} cos (2 x) (x^{2} - 3) - \int - x cos (2 x) d x

\int - x cos (2 x) d x = - \frac{1}{4} (2 x sin (2 x) + cos (2 x))

= - \frac{1}{2} cos (2 x) (x^{2} - 3) - (- \frac{1}{4} (2 x sin (2 x) + cos (2 x)))

Simplify

- \frac{1}{2} cos (2 x) (x^{2} - 3) - (- \frac{1}{4} (2 x sin (2 x) + cos (2 x))) : - \frac{1}{2} x^{2} cos (2 x) + \frac{1}{2} x sin (2 x) + \frac{7}{4} cos (2 x)

= - \frac{1}{2} x^{2} cos (2 x) + \frac{1}{2} x sin (2 x) + \frac{7}{4} cos (2 x)

Add a constant to the solution

= - \frac{1}{2} x^{2} cos (2 x) + \frac{1}{2} x sin (2 x) + \frac{7}{4} cos (2 x) + C

\frac{d}{d x} (sin (x) + sin (y) + sin (x + y))

\frac{1}{( x - 2 )}

\frac{d}{d x} (\frac{cos ( x ) - 1}{sin ( x )})

(2 e^{- t}) (cos (4 t)) (1 (t))

f (x) = 2 x^{3} + 3 x^{2} + 4 x + 2, at x = - 1

What is the integral of (x^2-3)sin(2x) ?
The integral of (x^2-3)sin(2x) is -1/2 x^2cos(2x)+1/2 xsin(2x)+7/4 cos(2x)+C