What is the solution for y^{''}+2y=18 ?

The solution for y^{''}+2y=18 is y=c_{1}cos(sqrt(2)t)+c_{2}sin(sqrt(2)t)+9

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y^{''}+2y=18

y^{^{''}} + 2 y = 18

y = c_{1} cos (2 t) + c_{2} sin (2 t) + 9

Solution steps

y^{''} (t) + 2 y = 18

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t) + 9

y = c_{1} cos (2 t) + c_{2} sin (2 t) + 9

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What is the solution for y^{''}+2y=18 ?
The solution for y^{''}+2y=18 is y=c_{1}cos(sqrt(2)t)+c_{2}sin(sqrt(2)t)+9