What is the solution for derivative of y=x^{0.1}(1+x) ?

The solution for derivative of y=x^{0.1}(1+x) is y=0.90909…x^{1.1}+0.47619…x^{2.1}+c_{1}

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derivative of y=x^{0.1}(1+x)

\frac{d}{d x} y = x^{0.1} (1 + x)

y = 0.90909 \dots x^{1.1} + 0.47619 \dots x^{2.1} + c_{1}

Solution steps

\frac{d y}{d x} = x^{0.1} (1 + x)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{0.1} (1 + x) d x

\int x^{0.1} (1 + x) d x = 0.90909 \dots x^{1.1} + 0.47619 \dots x^{2.1} + c_{1}

y = 0.90909 \dots x^{1.1} + 0.47619 \dots x^{2.1} + c_{1}

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What is the solution for derivative of y=x^{0.1}(1+x) ?
The solution for derivative of y=x^{0.1}(1+x) is y=0.90909…x^{1.1}+0.47619…x^{2.1}+c_{1}