What is the integral of (3x+11)/(x^2-x-6) ?

The integral of (3x+11)/(x^2-x-6) is -ln|x+2|+4ln|x-3|+C

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integral of (3x+11)/(x^2-x-6)

\int \frac{3 x + 11}{x ^{2} - x - 6} d x

- ln ∣ x + 2 ∣ + 4 ln ∣ x - 3 ∣ + C

Solution steps

\int \frac{3 x + 11}{x ^{2} - x - 6} d x

Take the partial fraction of

\frac{3 x + 11}{x ^{2} - x - 6} : - \frac{1}{x + 2} + \frac{4}{x - 3}

= \int - \frac{1}{x + 2} + \frac{4}{x - 3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{1}{x + 2} d x + \int \frac{4}{x - 3} d x

\int \frac{1}{x + 2} d x = ln ∣ x + 2 ∣

\int \frac{4}{x - 3} d x = 4 ln ∣ x - 3 ∣

= - ln ∣ x + 2 ∣ + 4 ln ∣ x - 3 ∣

Add a constant to the solution

= - ln ∣ x + 2 ∣ + 4 ln ∣ x - 3 ∣ + C

y = - 5 x^{\frac{1}{2}} + x^{\frac{3}{2}}

\frac{d y}{d x} = (y^{2} - 1) x

\frac{d}{d x} ((x^{2} + 3 x - 1) e^{x})

\int \frac{2}{3} x^{\frac{3}{2}} - 6 sin (x) + C d x

y^{^{'}} = x^{2} - 1, y (0) = 1

What is the integral of (3x+11)/(x^2-x-6) ?
The integral of (3x+11)/(x^2-x-6) is -ln|x+2|+4ln|x-3|+C