What is (\partial)/(\partial x)(cos(5x-2y^2)) ?

The answer to (\partial)/(\partial x)(cos(5x-2y^2)) is -sin(5x-2y^2)*5

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(\partial)/(\partial x)(cos(5x-2y^2))

\frac{\partial}{\partial x} (cos (5 x - 2 y^{2}))

- sin (5 x - 2 y^{2}) \cdot 5

Solution steps

\frac{\partial}{\partial x} (cos (5 x - 2 y^{2}))

Treat

y

as a constant

Apply the chain rule:

- sin (5 x - 2 y^{2}) \frac{\partial}{\partial x} (5 x - 2 y^{2})

= - sin (5 x - 2 y^{2}) \frac{\partial}{\partial x} (5 x - 2 y^{2})

\frac{\partial}{\partial x} (5 x - 2 y^{2}) = 5

= - sin (5 x - 2 y^{2}) \cdot 5

x^{2} + 8

n = 1 \sum \infty \frac{1}{4 n ^{6} + n + 1}

\frac{d y}{d x} = \frac{9 x}{y}

\int (\frac{1}{x \cdot ln ( x )}) d x

\int \frac{1}{x ^{2} - 4 x + 5} d x

What is (\partial)/(\partial x)(cos(5x-2y^2)) ?
The answer to (\partial)/(\partial x)(cos(5x-2y^2)) is -sin(5x-2y^2)*5