What is the sum from n=1 to infinity of 1/(4n^6+n+1) ?

The sum from n=1 to infinity of 1/(4n^6+n+1) is converges

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sum from n=1 to infinity of 1/(4n^6+n+1)

n = 1 \sum \infty \frac{1}{4 n ^{6} + n + 1}

converges

Solution steps

n = 1 \sum \infty \frac{1}{4 n ^{6} + n + 1}

Apply Series Comparison Test:

converges

= converges

\frac{d y}{d x} = \frac{9 x}{y}

\int (\frac{1}{x \cdot ln ( x )}) d x

\int \frac{1}{x ^{2} - 4 x + 5} d x

x^{2} y^{^{'}} + 2 x y = 15 cos^{2} (x)

\int_{- 1}^{2} x^{2} - 2 x d x

What is the sum from n=1 to infinity of 1/(4n^6+n+1) ?
The sum from n=1 to infinity of 1/(4n^6+n+1) is converges