What is the solution for (dy)/(dx)=(x+y-2)/(2x+2y+3) ?

The solution for (dy)/(dx)=(x+y-2)/(2x+2y+3) is y=-x-1/3+(7\W(2/(7e^{(-9x-c_{1)-14)/7}}))/(6)

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(dy)/(dx)=(x+y-2)/(2x+2y+3)

\frac{d y}{d x} = \frac{x + y - 2}{2 x + 2 y + 3}

y = - x - \frac{1}{3} + \frac{7 W ( \frac{2}{7 e ^{\frac{- 9 x - c _{1} - 14}{7}}} )}{6}

Solution steps

\frac{d y}{d x} = \frac{x + y - 2}{2 x + 2 y + 3}

Solve using substitution:

y = - x - \frac{1}{3} + \frac{7 W ( \frac{2}{7 e ^{\frac{- 9 x - c _{1} - 14}{7}}} )}{6}

y = - x - \frac{1}{3} + \frac{7 W ( \frac{2}{7 e ^{\frac{- 9 x - c _{1} - 14}{7}}} )}{6}

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What is the solution for (dy)/(dx)=(x+y-2)/(2x+2y+3) ?
The solution for (dy)/(dx)=(x+y-2)/(2x+2y+3) is y=-x-1/3+(7\W(2/(7e^{(-9x-c_{1)-14)/7}}))/(6)