What is the tangent of 6sec(x),\at x= pi/6 ?

The tangent of 6sec(x),\at x= pi/6 is y=4x+4sqrt(3)-(2pi)/3

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tangent of 6sec(x),\at x= pi/6

tangent of

6 sec (x), at x = \frac{π}{6}

y = 4 x + 43 - \frac{2 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{6}, 43)

Find the slope of

y = 6 sec (x) : \frac{d y}{d x} = 6 sec (x) tan (x)

Compute the slope of

y = 6 sec (x)

x = \frac{π}{6} : m = 4

Find the line with slope m=

4

and passing through

(\frac{π}{6}, 43) : y = 4 x + 43 - \frac{2 π}{3}

y = 4 x + 43 - \frac{2 π}{3}

\frac{d}{d x} (\frac{x + 1}{x ^{2} + x + 1})

x \to - 2 lim (f (x) x)

\frac{d}{d x} (cos (x (x^{2} + 1)) + \frac{3}{2})

x \to 0 lim (x ln (x + x^{2}))

\int \frac{x ^{2} - 64}{x} d x

What is the tangent of 6sec(x),\at x= pi/6 ?
The tangent of 6sec(x),\at x= pi/6 is y=4x+4sqrt(3)-(2pi)/3