en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

xy^'=y+(x+1)^2

Solution

x y^{^{'}} = y + (x + 1)^{2}

Solution

y = x^{2} + 2 x ln (x) - 1 + c_{1} x

Solution steps

x y^{'} (x) = y + (x + 1)^{2}

Solve linear ODE:

y = x^{2} + 2 x ln (x) - 1 + c_{1} x

y = x^{2} + 2 x ln (x) - 1 + c_{1} x

Popular Examples

integral of (x^5+x^3)^{11}(5x^4+3x^2)

\int (x^{5} + x^{3})^{11} (5 x^{4} + 3 x^{2}) d x

inverse oflaplace ((s-1))/(s^2(s^2+2))inverse laplace

\frac{( s - 1 )}{s ^{2} ( s ^{2} + 2 )}

integral of sec^5(x/2)

\int sec^{5} (\frac{x}{2}) d x

derivative of ln(tan(7x))

\frac{d}{d x} (ln (tan (7 x)))

derivative of f(x)=(x^7+5x)^{1/3}derivative of

f (x) = (x^{7} + 5 x)^{\frac{1}{3}}

Frequently Asked Questions (FAQ)

What is the solution for xy^'=y+(x+1)^2 ?
The solution for xy^'=y+(x+1)^2 is y=x^2+2xln(x)-1+c_{1}x