What is the first d/(dy)((y^2)/4) ?

The first d/(dy)((y^2)/4) is y/2

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d/(dy)((y^2)/4)

\frac{d}{d y} (\frac{y ^{2}}{4})

\frac{y}{2}

Solution steps

\frac{d}{d y} (\frac{y ^{2}}{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} \cdot 2 y^{2 - 1}

Simplify

\frac{1}{4} \cdot 2 y^{2 - 1} : \frac{y}{2}

= \frac{y}{2}

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