What is the integral from 0 to 5 of 1/(x^{5/2)} ?

The integral from 0 to 5 of 1/(x^{5/2)} is diverges

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integral from 0 to 5 of 1/(x^{5/2)}

\int_{0}^{5} \frac{1}{x ^{\frac{5}{2}}} d x

diverges

Solution steps

\int_{0}^{5} \frac{1}{x ^{\frac{5}{2}}} d x

Apply the Power Rule

: [- \frac{2}{3 x ^{\frac{3}{2}}}]_{0}^{5}

= [- \frac{2}{3 x ^{\frac{3}{2}}}]_{0}^{5}

Compute the boundaries:

diverges

= diverges

\int 3 x^{2} - 4 x + 1 d x

f (x) = (x^{2} + x + 1)^{3}

sin (ω \cdot t)

\int \frac{x ^{2} + x}{x - 1} d x

\frac{\partial}{\partial x} (5 - y^{3} - x^{7})

What is the integral from 0 to 5 of 1/(x^{5/2)} ?
The integral from 0 to 5 of 1/(x^{5/2)} is diverges