What is the derivative of (x^3/(x^2+1)) ?

The derivative of (x^3/(x^2+1)) is (x^4+3x^2)/((x^2+1)^2)

What is the first derivative of (x^3/(x^2+1)) ?

The first derivative of (x^3/(x^2+1)) is (x^4+3x^2)/((x^2+1)^2)

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\frac{d}{d x} (\frac{x ^{3}}{x ^{2} + 1})

\frac{x ^{4} + 3 x ^{2}}{( x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{x ^{2} + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{3} ) ( x ^{2} + 1 ) - \frac{d}{d x} ( x ^{2} + 1 ) x ^{3}}{( x ^{2} + 1 ) ^{2}}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2} + 1) = 2 x

= \frac{3 x ^{2} ( x ^{2} + 1 ) - 2 x x ^{3}}{( x ^{2} + 1 ) ^{2}}

Simplify

\frac{3 x ^{2} ( x ^{2} + 1 ) - 2 x x ^{3}}{( x ^{2} + 1 ) ^{2}} : \frac{x ^{4} + 3 x ^{2}}{( x ^{2} + 1 ) ^{2}}

= \frac{x ^{4} + 3 x ^{2}}{( x ^{2} + 1 ) ^{2}}

\frac{d y}{d x} = \frac{2 x}{y ( 1 + x ^{2} )}

f (x) = ln ((x - 1) (x + 1)^{2})

\int_{1}^{x^{3}} t^{2} d t

x \to 0 lim (\frac{e ^{- 5 x} - 1}{x})

\frac{d}{d x} (cos (5 x^{2} - x))

What is the derivative of (x^3/(x^2+1)) ?
The derivative of (x^3/(x^2+1)) is (x^4+3x^2)/((x^2+1)^2)
What is the first derivative of (x^3/(x^2+1)) ?
The first derivative of (x^3/(x^2+1)) is (x^4+3x^2)/((x^2+1)^2)