What is the derivative of x^{2cos(x)} ?

The derivative of x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)

What is the first derivative of x^{2cos(x)} ?

The first derivative of x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)

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derivative of

x^{2 c o s (x)}

2 x^{2 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

Solution steps

\frac{d}{d x} (x^{2 c o s (x)})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{2 c o s (x)} = e^{2 c o s (x) l n (x)}

= \frac{d}{d x} (e^{2 c o s (x) l n (x)})

Apply the chain rule:

e^{2 c o s (x) l n (x)} \frac{d}{d x} (2 cos (x) ln (x))

= e^{2 c o s (x) l n (x)} \frac{d}{d x} (2 cos (x) ln (x))

\frac{d}{d x} (2 cos (x) ln (x)) = 2 (- sin (x) ln (x) + \frac{cos ( x )}{x})

= e^{2 c o s (x) l n (x)} \cdot 2 (- sin (x) ln (x) + \frac{cos ( x )}{x})

e^{2 c o s (x) l n (x)} = x^{2 c o s (x)}

= 2 x^{2 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

x = 4 sin (t)

y = - 30 \frac{ln ( \frac{1}{40} )}{ln ( 2 )}

\frac{d}{d x} (\frac{2}{x - 2})

\frac{d}{d x} (5 e^{- x} + e^{4 x})

x^{3} y^{^{'''}} - x^{2} y^{^{''}} + 2 x y^{^{'}} - 2 y = x

What is the derivative of x^{2cos(x)} ?
The derivative of x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)
What is the first derivative of x^{2cos(x)} ?
The first derivative of x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)