What is the integral of (x^2)/2 1/x ?

The integral of (x^2)/2 1/x is (x^2)/4+C

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integral of (x^2)/2 1/x

\int \frac{x ^{2}}{2} \frac{1}{x} d x

\frac{x ^{2}}{4} + C

Solution steps

\int \frac{x ^{2}}{2} \cdot \frac{1}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int x^{2} \frac{1}{x} d x

Simplify

x^{2} \frac{1}{x} : x

= \frac{1}{2} \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= \frac{1}{2} \cdot \frac{x ^{2}}{2}

Simplify

\frac{1}{2} \cdot \frac{x ^{2}}{2} : \frac{x ^{2}}{4}

= \frac{x ^{2}}{4}

Add a constant to the solution

= \frac{x ^{2}}{4} + C

t^{2} \cdot sin (3 t)

\int (2 t + 3)^{- 2} d t

x e^{y} \frac{d y}{d x} + e^{y} = e^{x}

\frac{d}{d x} (e^{- \frac{x}{2}} sin (\frac{3}{2} x))

0.5 x^{3} 4^{x}