What is the solution for (4xe^x-y+9x^2)dx-xdy=0 ?

The solution for (4xe^x-y+9x^2)dx-xdy=0 is y=3x^2+(4(e^xx-e^x))/x+(c_{1})/x

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(4xe^x-y+9x^2)dx-xdy=0

(4 x e^{x} - y + 9 x^{2}) d x - x d y = 0

y = 3 x^{2} + \frac{4 ( e ^{x} x - e ^{x} )}{x} + \frac{c _{1}}{x}

Solution steps

(4 x e^{x} - y + 9 x^{2}) d x - x d y = 0

Solve linear ODE:

y = 3 x^{2} + \frac{4 ( e ^{x} x - e ^{x} )}{x} + \frac{c _{1}}{x}

y = 3 x^{2} + \frac{4 ( e ^{x} x - e ^{x} )}{x} + \frac{c _{1}}{x}

\int_{0}^{\frac{1}{13}} x ln (13 x) d x

y^{^{''}} - 12 y^{^{'}} + 45 y = 0

\frac{d}{d x} ((x - sin (x)) (x + cos (x)))

2 x \frac{d y}{d x} + y^{3} e^{- 2 x} = 2 x y

\int e^{x} \frac{1}{x} d x

What is the solution for (4xe^x-y+9x^2)dx-xdy=0 ?
The solution for (4xe^x-y+9x^2)dx-xdy=0 is y=3x^2+(4(e^xx-e^x))/x+(c_{1})/x